(8x^3+2x^2-6x)/(2x)=0

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Solution for (8x^3+2x^2-6x)/(2x)=0 equation: 


D( x )

2*x = 0

2*x = 0

2*x = 0

2*x = 0 // : 2

x = 0

x in (-oo:0) U (0:+oo)

(8*x^3+2*x^2-(6*x))/(2*x) = 0

(8*x^3+2*x^2-6*x)/(2*x) = 0

8*x^3+2*x^2-6*x = 0

2*x*(4*x^2+x-3) = 0

4*x^2+x-3 = 0

DELTA = 1^2-(-3*4*4)

DELTA = 49

DELTA > 0

x = (49^(1/2)-1)/(2*4) or x = (-49^(1/2)-1)/(2*4)

x = 3/4 or x = -1

2*x*(x+1)*(x-3/4) = 0

(x+1)*(x-3/4) = 0

( x+1 )

x+1 = 0 // - 1

x = -1

( x-3/4 )

x-3/4 = 0 // + 3/4

x = 3/4

x in { -1, 3/4 }

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